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Jun-te Kim 2026-01-22 17:05:38 +00:00
parent d5c9fd9390
commit 589f4a7961

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@ -3,10 +3,11 @@ import os
from urllib.parse import urlencode
import pandas as pd
from difflib import SequenceMatcher
from tqdm import tqdm
import re
EPC_AUTH_TOKEN = os.getenv("EPC_AUTH_TOKEN", "")
EPC_AUTH_TOKEN = os.getenv("EPC_AUTH_TOKEN", "a2Nvbm5rb3dsZXNzYXJAZ21haWwuY29tOjY5MGJiMWM0NmIyOGI5ZDUxYzAxMzQzYzNiZGNlZGJjZDNmODQwMzA=")
client = EpcClient(auth_token=EPC_AUTH_TOKEN)
import re
@ -292,30 +293,424 @@ def run_all_test():
test(get_uprn("68", "b93 8sy"), "100070989938")
test(get_uprn("68 Glendon Way", "b93 8sy"), "100070989938")
test(get_uprn("Flat A, 28, Nelgarde Road", "se6 4tf"), "100023278633")
test(get_uprn("28 A", "se6 4tf"), "100023278633")
test(get_uprn("28A", "se6 4tf"), "100023278633")
test(get_uprn("6 Aitken Close", "E8 4SQ"), False)
from epc_api.client import EpcClient
import os
from urllib.parse import urlencode
import pandas as pd
from difflib import SequenceMatcher
from tqdm import tqdm
get_uprn_candidates(get_epc_data_with_postcode("b93 8sy"), "68")
get_uprn_candidates(get_epc_data_with_postcode("se6 4tf"), "Flat A, 28, Nelgarde Road")
get_uprn_candidates(get_epc_data_with_postcode("se6 4tf"), "28 A")
get_uprn_candidates(get_epc_data_with_postcode("se6 4tf"), "A 28")
get_uprn_candidates(get_epc_data_with_postcode("se6 4tf"), "28A")
get_uprn_candidates(get_epc_data_with_postcode("se6 4tf"), "A28")
import re
get_uprn_candidates(get_epc_data_with_postcode("E8 4SQ"), "6 Aitken Close") # no epc
EPC_AUTH_TOKEN = os.getenv("EPC_AUTH_TOKEN", "a2Nvbm5rb3dsZXNzYXJAZ21haWwuY29tOjY5MGJiMWM0NmIyOGI5ZDUxYzAxMzQzYzNiZGNlZGJjZDNmODQwMzA=")
client = EpcClient(auth_token=EPC_AUTH_TOKEN)
import re
from difflib import SequenceMatcher
from typing import Set
def levenshtein(a: str, b: str) -> float:
"""
Address similarity score in [0, 1].
Strategy:
- Normalise
- Strongly penalise mismatched house/flat numbers
- Combine token overlap + character similarity
"""
def extract_numbers(s: str) -> Set[str]:
"""Extract all numeric tokens (house numbers, flat numbers)."""
return set(re.findall(r"\d+[a-z]?", s))
def tokenise(s: str) -> Set[str]:
return set(s.split())
a_norm = normalise_address(a)
b_norm = normalise_address(b)
# --- hard signal: numbers ---
nums_a = extract_numbers(a_norm)
nums_b = extract_numbers(b_norm)
if nums_a and nums_b and nums_a != nums_b:
# Different house/flat numbers → near impossible match
return 0.0
# --- token similarity (order-independent) ---
toks_a = tokenise(a_norm)
toks_b = tokenise(b_norm)
if not toks_a or not toks_b:
token_score = 0.0
else:
token_score = len(toks_a & toks_b) / len(toks_a | toks_b)
# --- character similarity (soft signal) ---
char_score = SequenceMatcher(None, a_norm, b_norm).ratio()
# --- weighted blend ---
return round(
0.65 * token_score +
0.35 * char_score,
4,
)
def normalise_address(s: str) -> str:
"""
Canonical UK-focused address normalisation.
- Lowercases
- Removes punctuation (keeps / for flats)
- Normalises whitespace
- Applies synonym compression at token level
"""
if not s:
return ""
ADDRESS_SYNONYMS = {
# street types
"rd": "road",
"rd.": "road",
"st": "street",
"st.": "street",
"ave": "avenue",
"ave.": "avenue",
"ln": "lane",
"ln.": "lane",
"cres": "crescent",
"ct": "court",
"dr": "drive",
# flats / units
"apt": "flat",
"apartment": "flat",
"unit": "flat",
"ste": "suite",
# numbering noise
"no": "",
"no.": "",
}
# 1. lowercase
s = s.lower()
# 2. remove punctuation except /
s = re.sub(r"[^\w\s/]", " ", s)
# 3. normalise whitespace
s = re.sub(r"\s+", " ", s).strip()
# 4. tokenise + synonym normalisation
tokens = []
for tok in s.split():
replacement = ADDRESS_SYNONYMS.get(tok, tok)
if replacement:
tokens.append(replacement)
return " ".join(tokens)
def score_addresses(
df: pd.DataFrame,
user_address: str,
column: str = "address",
) -> pd.Series:
if column not in df.columns:
raise ValueError(f"Missing column: {column}")
return df[column].apply(
lambda x: levenshtein(user_address, x)
)
def get_epc_data_with_postcode(postcode, size=500, attempt=1, max_attempts=3):
"""
Recursively fetch EPC data by postcode.
If results hit the size limit, retry with double size up to max_attempts.
"""
url = os.path.join(client.domestic.host, "search")
if size:
url += "?" + urlencode({"size": size})
search_resp = client.domestic.call(
url=url,
method="get",
params={"postcode": postcode},
)
results_df = pd.DataFrame(
search_resp["rows"],
columns=search_resp["column-names"]
)
row_count = len(results_df)
# If we hit the size limit, there *may* be more results
if row_count == size:
print(
f"⚠️ Warning: hit size limit ({size}) for postcode '{postcode}'. "
f"Attempt {attempt}/{max_attempts}."
)
if attempt < max_attempts:
print(f"🔁 Retrying with size={size * 2}")
return get_epc_data_with_postcode(
postcode=postcode,
size=size * 2,
attempt=attempt + 1,
max_attempts=max_attempts,
)
else:
print(
"🚨 Max attempts reached. Results may be truncated. "
"(Please do a manual review by the tech team.)"
)
return results_df
def df_has_single_uprn(df: pd.DataFrame, uprn: str, column: str = "uprn") -> bool:
"""
Returns True if all non-null UPRNs in df match the given uprn.
Returns False otherwise.
"""
if column not in df.columns:
return False
# Drop nulls and normalise to string
uprns = (
df[column]
.dropna()
.astype(str)
.str.strip()
.unique()
)
# No valid UPRNs to compare
if len(uprns) == 0:
return False
# Exactly one unique UPRN and it matches
return len(uprns) == 1 and uprns[0] == str(uprn)
def get_uprn_candidates(
df: pd.DataFrame,
user_address: str,
address_column: str = "address",
uprn_column: str = "uprn",
) -> pd.DataFrame:
"""
Annotate EPC results with lexicographical similarity scores and ranks.
Returns a DataFrame sorted by descending lexiscore.
DOES NOT choose or return a UPRN.
"""
if address_column not in df.columns:
raise ValueError(f"Missing column: {address_column}")
if uprn_column not in df.columns:
raise ValueError(f"Missing column: {uprn_column}")
out = df.copy()
user_norm = normalise_address(user_address)
out["lexiscore"] = out[address_column].apply(
lambda x: levenshtein(user_norm, x)
)
# Normalise UPRN to string
out[uprn_column] = (
out[uprn_column]
.astype(str)
.str.replace(r"\.0$", "", regex=True)
)
# Rank: 1 = best match
out["lexirank"] = (
out["lexiscore"]
.rank(method="dense", ascending=False)
.astype(int)
)
return out.sort_values(
["lexirank", "lexiscore"],
ascending=[True, False],
)
def get_uprn(user_inputed_address: str, postcode: str):
df = get_epc_data_with_postcode(postcode=postcode)
if df.empty:
return False
scored_df = get_uprn_candidates(
df,
user_address=user_inputed_address,
)
# Best score
best_score = scored_df.iloc[0]["lexiscore"]
if best_score <= 0:
return False
# All rank-1 rows (possible draw)
top_rank_df = scored_df[scored_df["lexirank"] == 1]
# If rank-1 rows do not agree on a single UPRN → ambiguous
if not df_has_single_uprn(top_rank_df, uprn=top_rank_df.iloc[0]["uprn"]):
return False
# Safe to return the agreed UPRN
return top_rank_df.iloc[0]["uprn"]
def test(a,b):
assert a == b, f"errr a {a} - {type(a)}, does not equal b {b} - {type(b)}"
def run_all_test():
# Basic usage with different post codes styles
test(get_epc_data_with_postcode("b93 8sy").shape[0], 63)
test(get_epc_data_with_postcode("B938sy").shape[0], 63)
test(get_epc_data_with_postcode("b93 8Sy").shape[0], 63)
test(get_epc_data_with_postcode("b93 8Sy").shape[0], 63)
test(get_uprn("68", "b93 8sy"), "100070989938")
test(get_uprn("68 Glendon Way", "b93 8sy"), "100070989938")
test(get_uprn("Flat A, 28, Nelgarde Road", "se6 4tf"), "100023278633")
test(get_uprn("28 A", "se6 4tf"), "100023278633")
test(get_uprn("28A", "se6 4tf"), "100023278633")
test(get_uprn("6 Aitken Close", "E8 4SQ"), False)
# # Example of more than one results for the same address
# test(get_uprn("se6 4tf", house_number="flat A 28"), "100023278633")
# test(get_uprn("se6 4tf", house_number="28 A"), "100023278633")
# test(get_uprn("se6 4tf", house_number="A 28"), "100023278633")
# test(get_uprn("se6 4tf", house_number="A28"), "100023278633") # this one
# test(get_uprn("se6 4tf", house_number="28A"), "100023278633") # investigate this one
get_uprn_candidates(get_epc_data_with_postcode("E9 5NH"),"5 Semley Gate")
# # Example of flats that have different uprn
# test(get_uprn("se6 4tf", house_number="28"), "100023278633")
# TODO
# Lets write some tests with hackney and then peabody data
# house number nlp, address1
get_uprn_candidates(get_epc_data_with_postcode("E9 5NH"),"5 Semley Gate")
# get postcode
# make input data with peabody with 3 postcode so i have sample of iput
# TODO
# Lets write some tests with hackney and then peabody data
if __name__ == "__main__":
INPUT_FILE = "hackney.xlsx"
ADDRESS_COL = "Address 1"
POSTCODE_COL = "Postcode"
UPRN_COL = "UPRN"
df = pd.read_excel(INPUT_FILE)
failures = []
for _, row in tqdm(
df.iterrows(),
total=len(df),
desc="Auditing UPRNs",
):
input_address = str(row[ADDRESS_COL]).strip()
postcode = str(row[POSTCODE_COL]).strip()
expected_uprn = (
None
if pd.isna(row[UPRN_COL])
else str(int(row[UPRN_COL]))
)
try:
epc_df = get_epc_data_with_postcode(postcode)
if epc_df.empty:
failures.append({
**row.to_dict(),
"found_uprn": None,
"best_match_uprn": None,
"best_match_address": None,
"best_match_lexiscore": None,
"status": "no_epc_results",
})
continue
scored_df = get_uprn_candidates(
epc_df,
user_address=input_address,
)
best_row = scored_df.iloc[0]
best_match_uprn = str(best_row["uprn"])
best_match_address = best_row["address"]
best_match_lexiscore = round(float(best_row["lexiscore"]), 4)
found_uprn = get_uprn(input_address, postcode)
except Exception as e:
failures.append({
**row.to_dict(),
"found_uprn": None,
"best_match_uprn": None,
"best_match_address": None,
"best_match_lexiscore": None,
"status": "exception",
"error": str(e),
})
continue
found_uprn_norm = (
None if not found_uprn else str(found_uprn)
)
if found_uprn_norm != expected_uprn:
failures.append({
**row.to_dict(),
"found_uprn": found_uprn_norm,
"best_match_uprn": best_match_uprn,
"best_match_address": best_match_address,
"best_match_lexiscore": best_match_lexiscore,
"status": (
"no_match"
if found_uprn_norm is None
else "mismatch"
),
})
failures_df = pd.DataFrame(failures)
print("===================================")
print(f"Total rows : {len(df)}")
print(f"Failures : {len(failures_df)}")
print("===================================")
failures_df.to_excel(
"hackney_uprn_failures.xlsx",
index=False,
)
# TO do function dispatcher,
# get_uprn_candidates(get_epc_data_with_postcode("E9 5NH"),"Flat 1, 5 Semley Gate" and Flat 5, 1 Semley Gate)
# fix that
# Look again at flat 1
# pandas reader the seperate postcode_splitter
# dump into s3