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1 changed files with 416 additions and 21 deletions
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@ -3,10 +3,11 @@ import os
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from urllib.parse import urlencode
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import pandas as pd
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from difflib import SequenceMatcher
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from tqdm import tqdm
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import re
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EPC_AUTH_TOKEN = os.getenv("EPC_AUTH_TOKEN", "")
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EPC_AUTH_TOKEN = os.getenv("EPC_AUTH_TOKEN", "a2Nvbm5rb3dsZXNzYXJAZ21haWwuY29tOjY5MGJiMWM0NmIyOGI5ZDUxYzAxMzQzYzNiZGNlZGJjZDNmODQwMzA=")
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client = EpcClient(auth_token=EPC_AUTH_TOKEN)
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import re
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@ -292,30 +293,424 @@ def run_all_test():
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test(get_uprn("68", "b93 8sy"), "100070989938")
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test(get_uprn("68 Glendon Way", "b93 8sy"), "100070989938")
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test(get_uprn("Flat A, 28, Nelgarde Road", "se6 4tf"), "100023278633")
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test(get_uprn("28 A", "se6 4tf"), "100023278633")
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test(get_uprn("28A", "se6 4tf"), "100023278633")
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test(get_uprn("6 Aitken Close", "E8 4SQ"), False)
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from epc_api.client import EpcClient
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import os
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from urllib.parse import urlencode
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import pandas as pd
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from difflib import SequenceMatcher
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from tqdm import tqdm
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get_uprn_candidates(get_epc_data_with_postcode("b93 8sy"), "68")
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get_uprn_candidates(get_epc_data_with_postcode("se6 4tf"), "Flat A, 28, Nelgarde Road")
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get_uprn_candidates(get_epc_data_with_postcode("se6 4tf"), "28 A")
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get_uprn_candidates(get_epc_data_with_postcode("se6 4tf"), "A 28")
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get_uprn_candidates(get_epc_data_with_postcode("se6 4tf"), "28A")
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get_uprn_candidates(get_epc_data_with_postcode("se6 4tf"), "A28")
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import re
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get_uprn_candidates(get_epc_data_with_postcode("E8 4SQ"), "6 Aitken Close") # no epc
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EPC_AUTH_TOKEN = os.getenv("EPC_AUTH_TOKEN", "a2Nvbm5rb3dsZXNzYXJAZ21haWwuY29tOjY5MGJiMWM0NmIyOGI5ZDUxYzAxMzQzYzNiZGNlZGJjZDNmODQwMzA=")
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client = EpcClient(auth_token=EPC_AUTH_TOKEN)
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import re
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from difflib import SequenceMatcher
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from typing import Set
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def levenshtein(a: str, b: str) -> float:
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"""
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Address similarity score in [0, 1].
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Strategy:
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- Normalise
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- Strongly penalise mismatched house/flat numbers
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- Combine token overlap + character similarity
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"""
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def extract_numbers(s: str) -> Set[str]:
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"""Extract all numeric tokens (house numbers, flat numbers)."""
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return set(re.findall(r"\d+[a-z]?", s))
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def tokenise(s: str) -> Set[str]:
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return set(s.split())
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a_norm = normalise_address(a)
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b_norm = normalise_address(b)
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# --- hard signal: numbers ---
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nums_a = extract_numbers(a_norm)
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nums_b = extract_numbers(b_norm)
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if nums_a and nums_b and nums_a != nums_b:
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# Different house/flat numbers → near impossible match
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return 0.0
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# --- token similarity (order-independent) ---
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toks_a = tokenise(a_norm)
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toks_b = tokenise(b_norm)
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if not toks_a or not toks_b:
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token_score = 0.0
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else:
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token_score = len(toks_a & toks_b) / len(toks_a | toks_b)
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# --- character similarity (soft signal) ---
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char_score = SequenceMatcher(None, a_norm, b_norm).ratio()
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# --- weighted blend ---
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return round(
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0.65 * token_score +
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0.35 * char_score,
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4,
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)
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def normalise_address(s: str) -> str:
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"""
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Canonical UK-focused address normalisation.
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- Lowercases
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- Removes punctuation (keeps / for flats)
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- Normalises whitespace
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- Applies synonym compression at token level
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"""
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if not s:
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return ""
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ADDRESS_SYNONYMS = {
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# street types
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"rd": "road",
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"rd.": "road",
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"st": "street",
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"st.": "street",
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"ave": "avenue",
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"ave.": "avenue",
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"ln": "lane",
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"ln.": "lane",
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"cres": "crescent",
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"ct": "court",
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"dr": "drive",
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# flats / units
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"apt": "flat",
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"apartment": "flat",
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"unit": "flat",
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"ste": "suite",
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# numbering noise
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"no": "",
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"no.": "",
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}
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# 1. lowercase
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s = s.lower()
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# 2. remove punctuation except /
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s = re.sub(r"[^\w\s/]", " ", s)
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# 3. normalise whitespace
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s = re.sub(r"\s+", " ", s).strip()
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# 4. tokenise + synonym normalisation
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tokens = []
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for tok in s.split():
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replacement = ADDRESS_SYNONYMS.get(tok, tok)
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if replacement:
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tokens.append(replacement)
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return " ".join(tokens)
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def score_addresses(
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df: pd.DataFrame,
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user_address: str,
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column: str = "address",
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) -> pd.Series:
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if column not in df.columns:
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raise ValueError(f"Missing column: {column}")
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return df[column].apply(
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lambda x: levenshtein(user_address, x)
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)
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def get_epc_data_with_postcode(postcode, size=500, attempt=1, max_attempts=3):
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"""
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Recursively fetch EPC data by postcode.
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If results hit the size limit, retry with double size up to max_attempts.
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"""
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url = os.path.join(client.domestic.host, "search")
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if size:
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url += "?" + urlencode({"size": size})
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search_resp = client.domestic.call(
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url=url,
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method="get",
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params={"postcode": postcode},
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)
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results_df = pd.DataFrame(
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search_resp["rows"],
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columns=search_resp["column-names"]
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)
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row_count = len(results_df)
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# If we hit the size limit, there *may* be more results
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if row_count == size:
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print(
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f"⚠️ Warning: hit size limit ({size}) for postcode '{postcode}'. "
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f"Attempt {attempt}/{max_attempts}."
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)
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if attempt < max_attempts:
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print(f"🔁 Retrying with size={size * 2}")
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return get_epc_data_with_postcode(
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postcode=postcode,
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size=size * 2,
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attempt=attempt + 1,
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max_attempts=max_attempts,
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)
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else:
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print(
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"🚨 Max attempts reached. Results may be truncated. "
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"(Please do a manual review by the tech team.)"
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)
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return results_df
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def df_has_single_uprn(df: pd.DataFrame, uprn: str, column: str = "uprn") -> bool:
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"""
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Returns True if all non-null UPRNs in df match the given uprn.
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Returns False otherwise.
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"""
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if column not in df.columns:
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return False
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# Drop nulls and normalise to string
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uprns = (
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df[column]
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.dropna()
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.astype(str)
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.str.strip()
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.unique()
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)
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# No valid UPRNs to compare
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if len(uprns) == 0:
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return False
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# Exactly one unique UPRN and it matches
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return len(uprns) == 1 and uprns[0] == str(uprn)
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def get_uprn_candidates(
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df: pd.DataFrame,
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user_address: str,
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address_column: str = "address",
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uprn_column: str = "uprn",
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) -> pd.DataFrame:
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"""
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Annotate EPC results with lexicographical similarity scores and ranks.
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Returns a DataFrame sorted by descending lexiscore.
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DOES NOT choose or return a UPRN.
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"""
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if address_column not in df.columns:
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raise ValueError(f"Missing column: {address_column}")
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if uprn_column not in df.columns:
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raise ValueError(f"Missing column: {uprn_column}")
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out = df.copy()
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user_norm = normalise_address(user_address)
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out["lexiscore"] = out[address_column].apply(
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lambda x: levenshtein(user_norm, x)
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)
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# Normalise UPRN to string
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out[uprn_column] = (
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out[uprn_column]
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.astype(str)
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.str.replace(r"\.0$", "", regex=True)
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)
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# Rank: 1 = best match
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out["lexirank"] = (
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out["lexiscore"]
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.rank(method="dense", ascending=False)
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.astype(int)
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)
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return out.sort_values(
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["lexirank", "lexiscore"],
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ascending=[True, False],
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)
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def get_uprn(user_inputed_address: str, postcode: str):
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df = get_epc_data_with_postcode(postcode=postcode)
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if df.empty:
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return False
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scored_df = get_uprn_candidates(
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df,
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user_address=user_inputed_address,
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)
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# Best score
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best_score = scored_df.iloc[0]["lexiscore"]
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if best_score <= 0:
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return False
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# All rank-1 rows (possible draw)
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top_rank_df = scored_df[scored_df["lexirank"] == 1]
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# If rank-1 rows do not agree on a single UPRN → ambiguous
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if not df_has_single_uprn(top_rank_df, uprn=top_rank_df.iloc[0]["uprn"]):
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return False
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# Safe to return the agreed UPRN
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return top_rank_df.iloc[0]["uprn"]
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def test(a,b):
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assert a == b, f"errr a {a} - {type(a)}, does not equal b {b} - {type(b)}"
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def run_all_test():
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# Basic usage with different post codes styles
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test(get_epc_data_with_postcode("b93 8sy").shape[0], 63)
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test(get_epc_data_with_postcode("B938sy").shape[0], 63)
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test(get_epc_data_with_postcode("b93 8Sy").shape[0], 63)
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test(get_epc_data_with_postcode("b93 8Sy").shape[0], 63)
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test(get_uprn("68", "b93 8sy"), "100070989938")
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test(get_uprn("68 Glendon Way", "b93 8sy"), "100070989938")
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test(get_uprn("Flat A, 28, Nelgarde Road", "se6 4tf"), "100023278633")
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test(get_uprn("28 A", "se6 4tf"), "100023278633")
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test(get_uprn("28A", "se6 4tf"), "100023278633")
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test(get_uprn("6 Aitken Close", "E8 4SQ"), False)
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# # Example of more than one results for the same address
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# test(get_uprn("se6 4tf", house_number="flat A 28"), "100023278633")
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# test(get_uprn("se6 4tf", house_number="28 A"), "100023278633")
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# test(get_uprn("se6 4tf", house_number="A 28"), "100023278633")
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# test(get_uprn("se6 4tf", house_number="A28"), "100023278633") # this one
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# test(get_uprn("se6 4tf", house_number="28A"), "100023278633") # investigate this one
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get_uprn_candidates(get_epc_data_with_postcode("E9 5NH"),"5 Semley Gate")
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# # Example of flats that have different uprn
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# test(get_uprn("se6 4tf", house_number="28"), "100023278633")
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# TODO
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# Lets write some tests with hackney and then peabody data
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# house number nlp, address1
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get_uprn_candidates(get_epc_data_with_postcode("E9 5NH"),"5 Semley Gate")
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# get postcode
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# make input data with peabody with 3 postcode so i have sample of iput
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# TODO
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# Lets write some tests with hackney and then peabody data
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if __name__ == "__main__":
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INPUT_FILE = "hackney.xlsx"
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ADDRESS_COL = "Address 1"
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POSTCODE_COL = "Postcode"
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UPRN_COL = "UPRN"
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df = pd.read_excel(INPUT_FILE)
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failures = []
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for _, row in tqdm(
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df.iterrows(),
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total=len(df),
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desc="Auditing UPRNs",
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):
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input_address = str(row[ADDRESS_COL]).strip()
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postcode = str(row[POSTCODE_COL]).strip()
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expected_uprn = (
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None
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if pd.isna(row[UPRN_COL])
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else str(int(row[UPRN_COL]))
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)
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try:
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epc_df = get_epc_data_with_postcode(postcode)
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if epc_df.empty:
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failures.append({
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**row.to_dict(),
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"found_uprn": None,
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"best_match_uprn": None,
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"best_match_address": None,
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"best_match_lexiscore": None,
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"status": "no_epc_results",
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})
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continue
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scored_df = get_uprn_candidates(
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epc_df,
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user_address=input_address,
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)
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best_row = scored_df.iloc[0]
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best_match_uprn = str(best_row["uprn"])
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best_match_address = best_row["address"]
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best_match_lexiscore = round(float(best_row["lexiscore"]), 4)
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found_uprn = get_uprn(input_address, postcode)
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except Exception as e:
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failures.append({
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**row.to_dict(),
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"found_uprn": None,
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"best_match_uprn": None,
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"best_match_address": None,
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"best_match_lexiscore": None,
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"status": "exception",
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"error": str(e),
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})
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continue
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found_uprn_norm = (
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None if not found_uprn else str(found_uprn)
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)
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if found_uprn_norm != expected_uprn:
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failures.append({
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**row.to_dict(),
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"found_uprn": found_uprn_norm,
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"best_match_uprn": best_match_uprn,
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"best_match_address": best_match_address,
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"best_match_lexiscore": best_match_lexiscore,
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"status": (
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"no_match"
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if found_uprn_norm is None
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else "mismatch"
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),
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})
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failures_df = pd.DataFrame(failures)
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print("===================================")
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print(f"Total rows : {len(df)}")
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print(f"Failures : {len(failures_df)}")
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print("===================================")
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failures_df.to_excel(
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"hackney_uprn_failures.xlsx",
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index=False,
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)
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# TO do function dispatcher,
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# get_uprn_candidates(get_epc_data_with_postcode("E9 5NH"),"Flat 1, 5 Semley Gate" and Flat 5, 1 Semley Gate)
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# fix that
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# Look again at flat 1
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# pandas reader the seperate postcode_splitter
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# dump into s3
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